Gas Stoichiometry Calculator

Combine the ideal gas law with stoichiometry to solve gas-related problems

Gas Stoichiometry Calculator

Ideal Gas Law: PV = nRT
Combine gas laws with stoichiometry to calculate volume, mass, or moles
At STP (0°C, 1 atm): 1 mol gas = 22.4 L

atm

K (Kelvin)

From balanced equation (e.g., 2 in 2H₂ + O₂ → 2H₂O)

mol - OR enter mass + molar mass below

grams (g)

g/mol

Common Gas Molar Masses (g/mol):

• H₂: 2.02
• O₂: 32.00
• N₂: 28.01
• CO₂: 44.01
• NH₃: 17.03
• CH₄: 16.04

What is Gas Stoichiometry?

Gas stoichiometry combines the ideal gas law (PV = nRT) with stoichiometric principles from balanced chemical equations. This allows us to relate the volume of gases to the amounts (moles, mass) of reactants and products in chemical reactions.

The Ideal Gas Law:

PV = nRT

  • P = Pressure (atm, Pa, mmHg)
  • V = Volume (L, m³)
  • n = Moles (mol)
  • R = Gas constant (0.0821 L·atm/(mol·K) or 8.314 J/(mol·K))
  • T = Temperature (K)

Standard Conditions

STP (Standard Temperature & Pressure)

  • • Temperature: 0°C (273.15 K)
  • • Pressure: 1 atm (101.325 kPa)
  • 1 mole of any gas = 22.4 L

This is the IUPAC standard reference point

Room Conditions

  • • Temperature: 25°C (298.15 K)
  • • Pressure: 1 atm
  • 1 mole of gas ≈ 24.5 L

Common laboratory conditions

Example Problems

Example 1: Finding Gas Volume at STP

Problem: What volume of CO₂ gas is produced when 8.8 g of CO₂ is formed at STP?

Given: mass = 8.8 g, M(CO₂) = 44.01 g/mol

Step 1: n = mass / M = 8.8 / 44.01 = 0.200 mol

Step 2: At STP, V = n × 22.4 L/mol = 0.200 × 22.4 = 4.48 L

Answer: 4.48 L of CO₂

Example 2: Stoichiometry with Gases

Problem: How many liters of O₂ at STP are needed to react with 2.5 L of H₂?
Reaction: 2H₂ + O₂ → 2H₂O

From equation: 2 mol H₂ requires 1 mol O₂

At same T and P: Volume ratio = Mole ratio

V(O₂) = V(H₂) × (1 mol O₂ / 2 mol H₂) = 2.5 × (1/2) = 1.25 L

Answer: 1.25 L of O₂

Example 3: Non-STP Conditions

Problem: Calculate the volume of 0.5 mol of N₂ at 25°C and 2 atm.

Given: n = 0.5 mol, T = 298 K, P = 2 atm, R = 0.0821 L·atm/(mol·K)

PV = nRT

V = nRT/P = (0.5 × 0.0821 × 298) / 2 = 6.13 L

Answer: 6.13 L of N₂

Avogadro's Law and Gas Volumes

Avogadro's Law states that equal volumes of all gases at the same temperature and pressure contain the same number of molecules (or moles).

V₁/n₁ = V₂/n₂ (at constant T and P)

This means volume ratios equal mole ratios for gases under the same conditions

This is extremely useful in stoichiometry because you can directly use volume ratios from balanced equations when working with gases at the same temperature and pressure.

Molar Volume at Different Conditions

ConditionsTemperature (K)Pressure (atm)Molar Volume (L/mol)
STP (IUPAC)273.151.00022.414
Room Temperature298.151.00024.465
High Pressure298.152.00012.232
High Temperature373.151.00030.620

Real-World Applications

🏭 Industrial Processes

  • • Haber process (NH₃ production): N₂ + 3H₂ → 2NH₃
  • • Calculating reactant volumes for chemical plants
  • • Designing reactor sizes and gas storage systems
  • • Optimizing fuel-air mixtures in combustion

🔬 Laboratory Work

  • • Gas collection experiments
  • • Determining yields of gaseous products
  • • Calibrating gas syringes and volumetric equipment
  • • Preparing specific gas concentrations

🌱 Environmental Science

  • • Calculating CO₂ emissions from combustion
  • • Measuring air pollutant concentrations
  • • Greenhouse gas inventories
  • • Atmospheric chemistry modeling

⚕️ Medical Applications

  • • Anesthetic gas delivery systems
  • • Oxygen therapy calculations
  • • Respiratory gas exchange analysis
  • • Scuba diving gas mixtures (nitrox, trimix)

Important Considerations

⚠️ Ideal Gas Assumptions

The ideal gas law assumes:

  • • Gas particles have no volume
  • • No intermolecular forces between particles
  • • Perfectly elastic collisions
  • • Random motion

Real gases deviate from ideal behavior at high pressures and low temperatures. Use the Van der Waals equation for more accurate calculations under these conditions.

📏 Unit Consistency

  • • Always use Kelvin for temperature (K = °C + 273.15)
  • • Match R constant with your units (0.0821 L·atm/(mol·K) or 8.314 J/(mol·K))
  • • Convert all measurements to compatible units before calculating
  • • Check significant figures based on given data

🔄 Stoichiometric Coefficients

Always balance your chemical equation first! The mole ratios from the balanced equation are critical for accurate stoichiometric calculations. For gases at the same T and P, volume ratios equal mole ratios.