Redox Balancing Calculator

Half-Reaction Method

Half-Reaction Method

Balance redox reactions by separating oxidation and reduction half-reactions, then combining them.

Example Reactions:

Common oxidation half-reactions
Common reduction half-reactions

Half-Reaction Method Overview

The Half-Reaction Method balances redox reactions by treating oxidation and reduction separately, then combining them.

  1. Separate into oxidation and reduction half-reactions
  2. Balance atoms except O and H
  3. Balance O by adding H₂O
  4. Balance H by adding H⁺ (acidic) or OH⁻ (basic)
  5. Balance charge by adding electrons (e⁻)
  6. Multiply to equalize electrons transferred
  7. Add half-reactions and cancel common terms

Remember: In acidic solutions use H⁺ and H₂O. In basic solutions, balance as if acidic, then add OH⁻ to neutralize all H⁺ ions, creating H₂O.

Understanding the Bohr Model of the Hydrogen Atom

What is the Bohr Model?

The Bohr model, proposed by Niels Bohr in 1913, was a revolutionary quantum mechanical model of the hydrogen atom. It introduced the concept of quantized energy levels, explaining why atoms emit light at specific wavelengths rather than a continuous spectrum.

While the Bohr model has been superseded by more accurate quantum mechanical models (Schrödinger equation), it remains incredibly useful for understanding atomic structure and calculating the hydrogen spectrum. It successfully explains the Rydberg formula and predicts the correct wavelengths for hydrogen's spectral lines.

Key Equations

Energy of Level n:

En = -13.6 eV / n²

  • En = energy of electron in level n (eV or Joules)
  • n = principal quantum number (1, 2, 3, ...)
  • -13.6 eV = ground state energy of hydrogen
  • Negative values indicate bound states (electron is trapped)

Energy of Transition:

ΔE = En₂ - En₁ = hf = hc/λ

  • ΔE = energy difference between levels
  • n₂ = upper (initial) level, n₁ = lower (final) level
  • For emission: ΔE is released as a photon
  • For absorption: ΔE must be provided to promote electron

Rydberg Equation:

1/λ = RH (1/n₁² - 1/n₂²)

  • λ = wavelength of emitted/absorbed light
  • RH = Rydberg constant = 1.097 × 10⁷ m⁻¹
  • n₁ = lower level, n₂ = upper level (n₂ > n₁)
  • Directly relates energy levels to spectral lines

Energy Level Diagram

The energy levels of hydrogen get closer together as n increases, asymptotically approaching zero energy (ionization) at n = ∞. The largest energy gap is between n = 1 and n = 2.

n = ∞E = 0 eV (ionization)
n = 5E = -0.544 eV
n = 4E = -0.850 eV
n = 3E = -1.511 eV
n = 2E = -3.400 eV
n = 1 (ground state)E = -13.6 eV

Energy increases (becomes less negative) as n increases. Ground state (n=1) is most stable.

Hydrogen Spectral Series

When electrons transition between energy levels, they emit or absorb photons. Each series is named after its discoverer and corresponds to transitions ending at a particular n₁ level:

Seriesn₁n₂ RangeRegionλ Range
Lyman12, 3, 4, ...Ultraviolet91-122 nm
Balmer23, 4, 5, ...Visible365-656 nm
Paschen34, 5, 6, ...Infrared820-1875 nm
Brackett45, 6, 7, ...Infrared1.46-4.05 μm
Pfund56, 7, 8, ...Infrared2.28-7.46 μm

Balmer Series: The only series visible to the human eye! These transitions (n → 2) produce the characteristic red, blue-green, blue-violet, and violet lines of hydrogen's spectrum. The Hα line (n=3→2) at 656 nm is prominently red.

Worked Example: Balmer Alpha (Hα)

Problem:

Calculate the wavelength of light emitted when an electron in hydrogen transitions from n = 3 to n = 2 (the Balmer alpha or Hα line).

Step 1: Calculate energy of each level

E₂ = -13.6 eV / 2² = -13.6 / 4 = -3.40 eV

E₃ = -13.6 eV / 3² = -13.6 / 9 = -1.51 eV

Step 2: Calculate energy difference

ΔE = E₃ - E₂ = -1.51 - (-3.40) = 1.89 eV

Convert to Joules: 1.89 eV × 1.602×10⁻¹⁹ J/eV = 3.03×10⁻¹⁹ J

Step 3: Calculate wavelength using E = hc/λ

λ = hc / ΔE

λ = (6.626×10⁻³⁴ J·s)(2.998×10⁸ m/s) / (3.03×10⁻¹⁹ J)

λ = 6.56 × 10⁻⁷ m = 656 nm

Alternative: Use Rydberg equation

1/λ = RH (1/n₁² - 1/n₂²)

1/λ = 1.097×10⁷ (1/4 - 1/9) = 1.097×10⁷ (0.1389)

1/λ = 1.524×10⁶ m⁻¹

λ = 656 nm ✓

Answer:

The Hα line has a wavelength of 656 nm, which appears as red lightin the visible spectrum. This is one of the most prominent lines in hydrogen's emission spectrum and is used extensively in astronomy.

Applications of the Bohr Model

🌌Astronomy

Hydrogen spectral lines (especially Hα) are used to study stars, nebulae, and galaxies. Redshift/blueshift of these lines reveals the velocity and distance of celestial objects.

🔬Spectroscopy

Emission and absorption spectroscopy identify elements in unknown samples. Each element has a unique spectral fingerprint based on its electronic structure.

⚛️Quantum Mechanics

The Bohr model introduced quantization of energy, laying the groundwork for modern quantum mechanics. It demonstrated that classical physics fails at the atomic scale.

💡Plasma Physics

Understanding hydrogen spectra is crucial for fusion research and plasma diagnostics. The Balmer lines are monitored in fusion reactors to measure plasma conditions.

Limitations of the Bohr Model

While successful for hydrogen, the Bohr model has significant limitations:

Only works for hydrogen-like ions

Cannot accurately predict spectra of multi-electron atoms

Doesn't explain fine structure

Cannot account for splitting of spectral lines in magnetic fields (Zeeman effect)

Violates Heisenberg uncertainty principle

Assumes precise knowledge of both position and momentum

No explanation for chemical bonding

Cannot predict molecular structures or bond formation

Modern Replacement: The Schrödinger equation and quantum mechanical orbital theory provide a more complete and accurate description of atomic structure, though the Bohr model remains pedagogically valuable.

Historical Significance

1885: Johann Balmer

Empirically discovered the formula for hydrogen's visible spectral lines (Balmer series), not knowing the underlying physics.

1888: Johannes Rydberg

Generalized Balmer's formula to the Rydberg equation, covering all spectral series. Introduced the Rydberg constant.

1913: Niels Bohr

Developed quantum model explaining WHY the Rydberg equation works. Introduced quantized angular momentum and stationary states. Won 1922 Nobel Prize.

1926: Erwin Schrödinger

Formulated wave equation that completely describes atomic structure, superseding Bohr's model while confirming its main results for hydrogen.

Quick Reference Guide

Key Equations:

  • En = -13.6 eV / n²
  • ΔE = Eupper - Elower
  • 1/λ = RH(1/n₁² - 1/n₂²)
  • RH = 1.097×10⁷ m⁻¹

Famous Lines:

  • Hα (n=3→2): 656 nm (red)
  • Hβ (n=4→2): 486 nm (blue-green)
  • Hγ (n=5→2): 434 nm (violet)
  • Lyman α (n=2→1): 121 nm (UV)