Calculate gas diffusion and effusion rates based on molar mass using Graham's Law
Graham's Law: rate₁/rate₂ = √(M₂/M₁)
The rate of diffusion or effusion is inversely proportional to the square root of molar mass
Same units as rate₁
g/mol
g/mol
Graham's Law states that the rate of diffusion or effusion of a gas is inversely proportional to the square root of its molar mass.
rate₁/rate₂ = √(M₂/M₁)
Diffusion
Movement of gas molecules through another gas or medium
Effusion
Escape of gas molecules through a tiny hole into a vacuum
Problem:
If helium (He, M = 4.00 g/mol) effuses at a rate of 10.0 mL/min, how fast will oxygen (O₂, M = 32.00 g/mol) effuse?
Step 1: Identify values
rateHe = 10.0 mL/min
MHe = 4.00 g/mol
MO₂ = 32.00 g/mol
Step 2: Apply Graham's Law
rateHe/rateO₂ = √(MO₂/MHe)
Step 3: Calculate
10.0/rateO₂ = √(32.00/4.00)
10.0/rateO₂ = √8 = 2.828
rateO₂ = 10.0/2.828 = 3.54 mL/min
Result:
Helium effuses 2.83 times faster than oxygen because it's much lighter.
Relative to oxygen (O₂ = 1.00):
| Gas | M (g/mol) | Relative Rate |
|---|---|---|
| H₂ | 2.02 | 3.98× |
| He | 4.00 | 2.83× |
| CH₄ | 16.04 | 1.41× |
| N₂ | 28.01 | 1.07× |
| O₂ | 32.00 | 1.00× |
| CO₂ | 44.01 | 0.85× |
| Cl₂ | 70.90 | 0.67× |
Graham's Law is used to separate uranium-235 from uranium-238 for nuclear fuel:
UF₆ (²³⁵U): M = 349.03 g/mol
UF₆ (²³⁸U): M = 352.04 g/mol
Rate Ratio:
rate₂₃₅/rate₂₃₈ = √(352.04/349.03) = 1.0043
²³⁵UF₆ effuses only 0.43% faster! Requires thousands of stages.
vrms = √(3RT/M)
R = 8.314 J/(mol·K), T = temperature (K), M = molar mass (kg/mol)
Graham's Law comes from the fact that rate ∝ velocity ∝ 1/√M
| Gas | vrms (m/s) |
|---|---|
| H₂ | 1927 |
| He | 1363 |
| N₂ | 515 |
| O₂ | 482 |