Freezing Point Depression Calculator

Freezing Point Depression Calculator

Freezing Point Depression Formula

ΔTf = i × Kf × m

Non-electrolytes: i = 1 | NaCl, KCl: i ≈ 2 | CaCl₂, Na₂SO₄: i ≈ 3

Common Kf Values (°C·kg/mol):

Water: 1.86
Benzene: 5.12
Cyclohexane: 20.0
Acetic acid: 3.90
Camphor: 37.7
Naphthalene: 6.94

Practical Applications:

  • Road salt (NaCl): Lowers freezing point of water to prevent ice formation
  • Antifreeze (ethylene glycol): Prevents car radiator from freezing
  • De-icing aircraft: Propylene glycol solutions lower freezing point
  • Ice cream making: Salt lowers ice temperature for faster freezing

What This Calculator Does

The Freezing Point Depression Calculator calculates how much a solvent's freezing point decreases when a solute is dissolved in it. This is a colligative property, meaning it depends on the number of dissolved particles, not their chemical identity.

When you add antifreeze to water, salt to ice, or any solute to a solvent, the freezing point drops. This calculator uses the formula ΔTf = Kf × m × i to calculate this depression, where:

  • ΔTf - Freezing point depression (temperature decrease in °C or K)
  • Kf - Cryoscopic constant (specific to each solvent)
  • m - Molality of the solution (mol solute/kg solvent)
  • i - Van't Hoff factor (number of particles per formula unit)

Formula & Calculation Method

Core Formula

ΔTf = Kf × m × i

Where:

  • ΔTf = Freezing point depression (°C)
  • Kf = Cryoscopic constant (°C·kg/mol)
  • m = Molality (mol/kg)
  • i = Van't Hoff factor (dimensionless)

Common Kf Values:

Water: 1.86 °C·kg/mol

Benzene: 5.12 °C·kg/mol

Cyclohexane: 20.0 °C·kg/mol

Acetic acid: 3.90 °C·kg/mol

Van't Hoff Factor (i):

Non-electrolytes (sugar, ethylene glycol): i = 1

NaCl: i ≈ 2 (Na⁺ + Cl⁻)

MgCl₂: i ≈ 3 (Mg²⁺ + 2Cl⁻)

CaCl₂: i ≈ 3 (Ca²⁺ + 2Cl⁻)

Step-by-Step Example

Problem: What is the freezing point of a solution made by dissolving 62 g of ethylene glycol (C₂H₆O₂) in 250 g of water?

Step 1: Calculate molality

Molar mass of C₂H₆O₂ = 62 g/mol

Moles = 62 g ÷ 62 g/mol = 1.00 mol

m = 1.00 mol ÷ 0.250 kg = 4.00 m

Step 2: Identify constants

Kf (water) = 1.86 °C·kg/mol

i (ethylene glycol) = 1 (non-electrolyte)

Step 3: Calculate ΔTf

ΔTf = 1.86 × 4.00 × 1 = 7.44 °C

Step 4: Find new freezing point

Normal FP of water = 0.0 °C

New FP = 0.0 - 7.44 = -7.44 °C

Real-World Applications

🚗 Antifreeze

Ethylene glycol in car radiators prevents coolant from freezing in winter. A 50/50 mixture provides protection down to -37°C (-34°F).

🧂 De-icing

Salt (NaCl, CaCl₂) on roads melts ice by lowering freezing point. CaCl₂ is more effective because it produces 3 ions and works at lower temperatures.

🍦 Ice Cream

Salt added to ice in hand-cranked ice cream makers lowers temperature below 0°C, allowing cream mixture to freeze properly.

🔬 Research

Determine molecular mass of unknown compounds. Cryoscopy is used in physical chemistry laboratories for molecular mass determination.

Quick Reference

Units

°C, mol/kg

Formula

ΔTf = Kf × m × i

Applications

Antifreeze, de-icing

Level

College chemistry

Where It's Used

🚗

Automotive

Engine antifreeze

🧂

Winter Roads

De-icing salt

🍦

Food Industry

Ice cream making

🔬

Research

Molecular mass